temp_c by status: a 26% spread

Breaking temp_c down by status on sensor-telemetry, because the headline average is 41.42 and no segment is actually there.

• fault — mean 51.81, median 49.85 (124 rows)
• warn — mean 45.55, median 45.53 (482 rows)
• ok — mean 40.98, median 40.97 (7,394 rows)

Top to bottom that is 51.81 against 40.98, a spread of 26.4%. The pooled average is 41.42.

select status,
  count(*)                                            as rows,
  round(avg(temp_c)::numeric, 2)                      as mean,
  percentile_cont(0.5) within group (order by temp_c) as median
from sensor_telemetry
group by 1
order by mean desc;

The groups are close enough that the pooled average is a fair summary. That is worth confirming rather than assuming: the check costs one query and the failure mode is invisible.

Notice the mean and median columns disagree only slightly here. Always compute both in the group-by. The comparison between them per segment is free and tells you whether you are looking at a level difference or a tail difference.

This is the setup for Simpson's paradox — the case where every segment moves one way and the total moves the other.