humidity_pct by site: a 0% spread

Breaking humidity_pct down by site on sensor-telemetry, because the headline average is 40.91 and no segment is actually there.

• SLT — mean 40.95, median 41.00 (2,822 rows)
• NOR — mean 40.90, median 40.90 (2,823 rows)
• RIV — mean 40.89, median 40.90 (2,355 rows)

Top to bottom that is 40.95 against 40.89, a spread of 0.2%. The pooled average is 40.91.

select site,
  count(*)                                                  as rows,
  round(avg(humidity_pct)::numeric, 2)                      as mean,
  percentile_cont(0.5) within group (order by humidity_pct) as median
from sensor_telemetry
group by 1
order by mean desc;

The groups are close enough that the pooled average is a fair summary. That is worth confirming rather than assuming: the check costs one query and the failure mode is invisible.

Notice the mean and median columns disagree only slightly here. Always compute both in the group-by. The comparison between them per segment is free and tells you whether you are looking at a level difference or a tail difference.

This is the setup for Simpson's paradox — the case where every segment moves one way and the total moves the other.